使用vsql操作密态数据库
操作步骤
1、以操作系统用户vastbase登录CN(数据库实例)所在主机。
2、执行以下命令打开密态开关,连接密态数据库。
vsql -p 5432 vastbase -r -C
3、创建客户端主密钥CMK和列加密密钥CEK。创建CMK的语法请参考CREATE CLIENT MASTER KEY、创建的CEK的语法请参考CREATE COLUMN ENCRYPTION KEY。
创建客户端加密主密钥(CMK):
CREATE CLIENT MASTER KEY ImgCMK1 WITH (KEY_STORE = localkms, KEY_PATH = "key_path_value1", ALGORITHM = RSA_2048); CREATE CLIENT MASTER KEY ImgCMK WITH (KEY_STORE = localkms, KEY_PATH = "key_path_value2", ALGORITHM = RSA_2048); CREATE COLUMN ENCRYPTION KEY ImgCEK1 WITH VALUES (CLIENT_MASTER_KEY = ImgCMK1, ALGORITHM = AEAD_AES_256_CBC_HMAC_SHA256); CREATE COLUMN ENCRYPTION KEY ImgCEK WITH VALUES (CLIENT_MASTER_KEY = ImgCMK, ALGORITHM = AEAD_AES_256_CBC_HMAC_SHA256);
查询存储密钥信息的系统表结果如下。
SELECT * FROM gs_client_global_keys; SELECT column_key_name,column_key_distributed_id ,global_key_id,key_owner FROM gs_column_keys;
查询结果如下:
global_key_name | key_namespace | key_owner | key_acl | create_date -----------------+---------------+-----------+---------+---------------------------- imgcmk1 | 2200 | 10 | | 2021-04-21 11:04:00.656617 imgcmk | 2200 | 10 | | 2021-04-21 11:04:05.389746 (2 rows) column_key_name | column_key_distributed_id | global_key_id | key_owner -----------------+---------------------------+---------------+----------- imgcek1 | 760411027 | 16392 | 10 imgcek | 3618369306 | 16398 | 10 (2 rows)
4、创建加密表。
CREATE TABLE creditcard_info (id_number int, name text encrypted with (column_encryption_key = ImgCEK, encryption_type = DETERMINISTIC),credit_card varchar(19) encrypted with (column_encryption_key = ImgCEK1, encryption_type = DETERMINISTIC));
5、查询表的详细信息。
\d creditcard_info
查询结果为如下,Modifiers值为encrypted则表示该列是加密列。
Table "public.creditcard_info"
Column | Type | Modifiers
-------------+-------------------+------------
id_number | integer |
name | text | encrypted
credit_card | character varying | encrypted
6、向加密表插入数据并进行等值查询。
INSERT INTO creditcard_info VALUES (1,'joe','6217986500001288393');
INSERT INTO creditcard_info VALUES (2, 'joy','6219985678349800033');
select * from creditcard_info where name = 'joe';
select id_number,name from creditcard_info;
查询结果为如下:
id_number | name | credit_card
-----------+------+---------------------
1 | joe | 6217986500001288393
(1 row)
id_number | name
-----------+------------------------------------------------------------------------------------------------------------------------------------------------------
1 | x011aefabd754ded0a536a96664790622487c4d366d313aecd5839e410a46d29cba96a60e4831000000ee79056a114c9a6c041bb552b78052e912a8b730609142074c63791abebd0d38
2 | x011aefabd76853108eb406c0f90e7c773b71648fa6e2b8028cf634b49aec65b4fcfb376f3531000000f7471c8686682de215d09aa87113f6fb03884be2031ef4dd967afc6f7901646b
(2 rows)
使用非密态客户端查看该加密表数据时是密文。
7、(可选)对加密表进行alter和update操作。
ALTER TABLE creditcard_info ADD COLUMN age int ENCRYPTED WITH (COLUMN_ENCRYPTION_KEY = ImgCEK, ENCRYPTION_TYPE = DETERMINISTIC);
\d creditcard_info
ALTER TABLE creditcard_info DROP COLUMN age;
update creditcard_info set credit_card = '80000000011111111' where name = 'joy';
select * from creditcard_info where name = 'joy';
返回结果为如下:
ALTER TABLE
Table "public.creditcard_info"
Column | Type | Modifiers
-------------+-------------------+------------
id_number | integer |
name | text | encrypted
credit_card | character varying | encrypted
age | integer | encrypted
ALTER TABLE
UPDATE 1
id_number | name | credit_card
-----------+------+-------------------
2 | joy | 80000000011111111
(1 row)